A) \[ns\to (n-2)f\to np\to (n-1)d\]
B) \[ns\to (n-2)f\to (n-1)d\to np\]
C) \[ns\to np\to (n-1)d\to (n-2)f\]
D) \[ns\to (n-1)d\to (n-2)f\to np\]
Correct Answer: B
Solution :
[b] The sequence of filling electrons in sixth period: \[6s-4f-5d-6p\] i.e., \[(ns)\to (n-2)f\to (n-1)d\to np\]You need to login to perform this action.
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