A) Rate\[=K[A][B]\]
B) Rate\[=\frac{K}{4}{{[A]}^{2}}\]
C) Rate\[=K{{[A]}^{2}}{{[B]}^{0}}\]
D) Rate\[=K{{[A]}^{2}}{{[B]}^{2}}\]
Correct Answer: C
Solution :
[c] Let the rate law equation be \[r=k{{[A]}^{x}}{{[B]}^{y}}\] ...(1) when A = 2A, \[4r=k{{[2A]}^{x}}{{[B]}^{y}}\] ...(2) Divide (2) by(1) \[\frac{4r}{r}=\frac{k{{[2A]}^{x}}{{[B]}^{y}}}{k{{[A]}^{x}}{{[B]}^{y}}}\] \[\therefore \] \[4={{(2)}^{x}},\]Hence \[x=2\] when B = 2B, \[r=k{{[A]}^{x}}{{[2B]}^{y}}\] ...(3) \[\therefore \] 1 = Divide (3) by (1) \[\frac{r}{r}=\frac{k{{[A]}^{x}}{{[2B]}^{y}}}{k{{[A]}^{x}}{{[B]}^{y}}}{{(2)}^{y}}\] \[\therefore \]\[y=0\] \[\therefore \] Rate \[=k{{[A]}^{2}}{{[B]}^{0}}\]You need to login to perform this action.
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