A) 1.00 M
B) 2.00 M
C) 2.50 M
D) 4.00 M
Correct Answer: B
Solution :
[b] Given mass of solute \[(w)=120\,g\] mass of solvent \[(w)=1000\,g\] Mol. mass of solute \[=60\,g\] density of solution \[=1.12\,g/mL\] From the given data, Mass of solution \[=1000+120=1120\,g\] \[\because \]\[d=\frac{\text{Mol}\text{. mass}}{\text{V}}\] or \[V=\frac{\text{Mol}\text{. mass}}{\text{d}}\] Volume of solution \[V=\frac{1120}{1.12}=1000\,mL\] or = 1 litre Now molarity\[(M)=\frac{\text{W}}{\text{Mol}\text{.mass }\!\!\times\!\!\text{ V(lit}\text{.)}}\] \[=\frac{120}{60\times 1}=2M\]You need to login to perform this action.
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