A) 0 g
B) 0.108 g
C) 0.108 g
D) 1.08 g
Correct Answer: A
Solution :
[a] \[A{{g}^{+}}+{{\underset{1F}{\mathop{e}}\,}^{-}}\xrightarrow{{}}\underset{108\,g}{\mathop{Ag}}\,\] 1 F = 1 mole of electrons = 96500 C 0.01F= 1.08 g Ag; \[Ag\,\,\text{left}=\text{ }1.08-1.08=0\]You need to login to perform this action.
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