A) 5.4 mH
B) 162 mH
C) 0.006 mH
D) 0.0002 mH
Correct Answer: B
Solution :
[b] \[L={{\mu }_{0}}\,nI\] \[\therefore \] \[\frac{{{L}_{2}}}{{{L}_{1}}}=\frac{\mu }{{{\mu }_{0}}}\] ---- (\[\because \] n and I are same) \[\therefore \] \[{{L}_{2}}={{\mu }_{1}}{{L}_{1}}=900\times 0.18=162\,mH\]You need to login to perform this action.
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