A) \[{{P}_{A}}=P_{A}^{O}{{x}_{A}}\]
B) \[{{P}_{A}}=P_{A}^{O}{{x}_{A}}\left( \frac{1}{{{x}_{B}}} \right)\]
C) \[{{P}_{A}}=P_{A}^{O}{{x}_{B}}\]
D) \[P_{A}^{O}=P\left( \frac{{{x}_{A}}}{{{x}_{B}}} \right)\]
Correct Answer: C
Solution :
[c] According to Raoult's law \[{{P}_{A}}=P{{{}^\circ }_{A}}\times {{x}_{B}}\] (partial pressure of solvent is equal to pure pressure of solvent multiplied by mole fraction of solvent.You need to login to perform this action.
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