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NEET Sample Paper NEET Sample Test Paper-92

  • question_answer
    An electric bulb marked 40 W and 200V, is used in a circuit of supply voltage 100V. Now its power is

    A) 10 W    

    B)        20 W

    C) 40 W    

    D)        100 W

    Correct Answer: A

    Solution :

    [a]   Resistance of bulb \[=\frac{{{V}^{2}}}{P}=\frac{200\times 200}{40}=1000\Omega \] New power\[=\frac{{{V}^{2}}}{R}=\frac{100\times 100}{1000}=10W.\]


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