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NEET Sample Paper NEET Sample Test Paper-92

  • question_answer
    The height at which the acceleration due to gravity becomes \[\frac{g}{9}\]  (where g = the acceleration due to gravity on the surface of the earth) in terms of R, the radius of the earth, is

    A) \[\frac{R}{\sqrt{2}}\]                 

    B)        \[R/2\]

    C) \[\sqrt{2}R\]      

    D)        \[2\,R\]

    Correct Answer: D

    Solution :

    [d] We know that\[\frac{g'}{g}=\frac{{{R}^{2}}}{{{(R+h)}^{2}}}\] \[\therefore \] \[\frac{g/9}{g}={{\left[ \frac{R}{R+h} \right]}^{2}}\] \[\therefore \] \[\frac{R}{R+h}=\frac{1}{3}\] \[\therefore \] \[h=2R\]


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