NEET Sample Paper NEET Sample Test Paper-92

  • question_answer
    A mass m is suspended from a spring of force constant k and just touches another identical spring fixed to the floor as shown in the figure. The time period of small oscillations is

    A) \[2\pi \sqrt{\frac{m}{k}}\]                      

    B) \[\pi \sqrt{\frac{m}{k}}+\pi \sqrt{\frac{m}{k/2}}\]

    C) \[\pi \sqrt{\frac{m}{3k/2}}\]                   

    D) \[\pi \sqrt{\frac{m}{k}}+\pi \sqrt{\frac{m}{2k}}\]

    Correct Answer: D

    Solution :

    [d] When the spring undergoes displacement in the downward direction it completes one half oscillation while it completes another half oscillation in the upward direction. The total time period is \[T=\pi \sqrt{\frac{m}{k}+}\pi \sqrt{\frac{m}{2k}}\]


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