A) 1 : 2
B) 2 : 1
C) 4 : 1
D) 1 : 4
Correct Answer: B
Solution :
[b] Let W newton be the load suspended. Then \[Y=\frac{(W/{{A}_{1}})}{({{\ell }_{1}}/L)}=\frac{W\,\,L}{{{A}_{1}}{{\ell }_{1}}}\] ?(1) and \[Y=\frac{(W/{{A}_{2}})}{({{\ell }_{2}}/L)}=\frac{W\,\,L}{{{A}_{2}}{{\ell }_{2}}}\] ....(2) Dividing equation (1) by equation (2), we get \[1=\left( \frac{{{\ell }_{2}}}{{{\ell }_{1}}} \right)\left( \frac{{{A}_{2}}}{{{A}_{1}}} \right)=\left( \frac{{{\ell }_{2}}}{{{\ell }_{1}}} \right)\left( \frac{2}{1} \right)\] \[\therefore \]\[\frac{{{\ell }_{1}}}{{{\ell }_{2}}}=\frac{2}{1}\]or \[{{\ell }_{1}}:{{\ell }_{2}}=2:1\]
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