A) \[5\times {{10}^{-18}}\]
B) \[4\times {{10}^{1}}\]
C) \[3\times {{10}^{7}}\]
D) \[2\times {{10}^{-25}}\]
Correct Answer: B
Solution :
[b] \[E=hv=\frac{ch}{\lambda };\]and \[v=\frac{c}{\lambda }\] \[8\times {{10}^{15}}=\frac{3.0\times {{10}^{8}}}{\lambda }\] \[\therefore \] \[\lambda =\frac{3.0\times {{10}^{8}}}{8\times {{10}^{15}}}=0.37\times {{10}^{-7}}\] \[=37.5\times {{10}^{-9}}m=4\times {{10}^{1}}nm\]
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