question_answer

In the following reaction sequence : The compound I is:

A) \[\underset{\underset{Cl}{\mathop{|}}\,}{\mathop{C{{H}_{2}}}}\,-\underset{\underset{Cl}{\mathop{|}}\,}{\mathop{CH}}\,-C{{H}_{3}}\]

B) \[\underset{\underset{Cl}{\mathop{|}}\,}{\mathop{C{{H}_{2}}}}\,-\underset{\underset{Cl}{\mathop{|}}\,}{\mathop{C{{H}_{2}}}}\,-C{{H}_{3}}\]

C) \[CH-\underset{\underset{Cl}{\mathop{|}}\,}{\mathop{CH}}\,-C{{H}_{2}}-C{{H}_{3}}\]

D)

Correct Answer: D

Solution :

[d] \[\xrightarrow{KOH}C{{H}_{3}}-\overset{O}{\mathop{\overset{||}{\mathop{\underset{(II)}{\mathop{C}}\,}}\,}}\,-C{{H}_{3}}\xrightarrow[(II)\,\,{{H}_{2}}O/{{H}^{+}}]{(I)\,\,C{{H}_{3}}MgBr}\] \[C{{H}_{3}}-\overset{OH}{\mathop{\overset{|}{\mathop{\underset{\underset{3{}^\circ \,\,alcohol}{\mathop{C{{H}_{3}}}}\,}{\mathop{\underset{|}{\mathop{C}}\,}}\,}}\,}}\,-C{{H}_{3}}\xrightarrow[Lucas\,\,Test]{Anhy.\,\,ZnC{{l}_{3}}+HCl}Gives\,\,turbidity\,\,immediately\]