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NEET Sample Paper NEET Sample Test Paper-92

  • question_answer
    On the basis of the information available from the reaction \[\frac{4}{3}Al+{{O}_{2}}\xrightarrow{{}}\frac{2}{3}A{{l}_{2}}{{O}_{3}},\]\[\Delta G=-827\,kJ\,mo{{l}^{-1}}\] of \[{{O}_{2}},\] the minimum e.m.f. required to carry out electrolysis of \[A{{l}_{2}}{{O}_{3}}\] is \[(F=96500\,C\,mo{{l}^{-1}})\]

    A) 4.28 V  

    B)        6.42 V

    C) 8.56 V  

    D)        2.14 V

    Correct Answer: D

    Solution :

    [d] \[\frac{4}{3}Al+{{O}_{2}}\xrightarrow[{}]{}\frac{2}{3}A{{l}_{2}}{{O}_{3}};\]\[\Delta G=-827kJmo{{l}^{-1}}\] Number of electrons involved is 4 \[\left( \frac{2}{3}\times 6=4 \right)\] \[\Delta G{}^\circ =-nFE{}^\circ \] or \[\frac{827000}{4\times 96500}=E{}^\circ \] \[\therefore \]\[E{}^\circ =2.14V\]


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