| Element | Ionization | Enthalpy (KJ/mol) | |
| 1st | 2nd | 3rd | |
| A | 899 | 1757 | 14847 |
| B | 737 | 1450 | 7731 |
A) Both ?A? and ?B? belong to group-1 where ?B? comes below ?A?.
B) Both ?A? and ?B? belong to group-1 where ?A? comes below ?B?.
C) Both ?A' and ?B? belong to group-2 where ?B? comes below ?A?.
D) Both ?A? and ?B? belong to group-2 where ?A? comes below ?B?.
Correct Answer: C
Solution :
[c] Generally, the ionization enthalpies or energy increases from left to right in a period and decreases from top to bottom in a group. Several factor such as atomic radius, nuclear charge, shielding effect are responsible for change of ionization enthalpies. Here, 1st ionization enthalpy of A and B is greater than group I (\[Li\,520\,kJmo{{l}^{-1}}\]to\[Cs\,374\,kJmo{{l}^{-1}}\]), which means element A and B belong to group \[2-\]and all three given ionization enthalpy values are less for element B means B will come below A.
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