NEET Sample Paper NEET Sample Test Paper-92

  • question_answer
    The enthalpy of formation for \[{{C}_{2}}{{H}_{4}}(g)C{{O}_{2}}(g)\] and \[{{H}_{2}}O(1)\] at \[25{}^\circ C\] and 1 atm pressure are 52, \[-394\] and \[-286\,kJ\,mo{{l}^{-1}}\] respectively The enthalpy of combustion of \[{{C}_{2}}{{H}_{4}}(g)\] will be

    A) \[+1412\,kJ\,mo{{l}^{-1}}\]

    B)        \[-1412\,kJ\,mo{{l}^{-1}}\]

    C) \[141.2\,kJ\,mo{{l}^{-1}}\]

    D)        \[-141.2\,kJ\,mo{{l}^{-1}}\]

    Correct Answer: B

    Solution :

    [b]   Desired eqn; \[{{C}_{2}}{{H}_{4}}+3{{O}_{2}}\xrightarrow[{}]{}2C{{O}_{2}}+2{{H}_{2}}O\] \[\Delta H=2(-394)+2(-286)-(52)=-1412\,kJ\]


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