| Element | \[{{M}^{3+}}/M\] | \[{{M}^{+}}/M\] |
| Al | \[-1.66\] | \[+0.55\] |
| TI | \[+1.26\] | \[-0.34\] |
A) \[T{{l}^{+}}\] is more stable than \[A{{l}^{3+}}\]
B) \[A{{l}^{+}}\] is more stable than \[A{{l}^{3+}}\]
C) \[T{{l}^{+}}\] is more stable than \[A{{l}^{+}}\]
D) \[T{{l}^{3+}}\] is more stable than \[A{{l}^{3+}}\]
Correct Answer: C
Solution :
[c] (i) \[\underset{Most\,\,stable}{\mathop{A{{l}^{3+}}}}\,\xrightarrow{E{}^\circ =-1.66}Al\]\[\xleftarrow{E{}^\circ =+0.55}\underset{Less\,\,stable}{\mathop{A{{l}^{+}}}}\,\] (ii)\[\underset{Less\,\,stable}{\mathop{T{{l}^{3+}}}}\,\xrightarrow{E{}^\circ =+1.26}Tl\]\[\xleftarrow{E{}^\circ =-0.34}\underset{More\,\,stable}{\mathop{T{{l}^{+}}}}\,\] \[T{{l}^{+}}\] has negative electrode potential \[(E{}^\circ =-0.34)\] means, it does not prefer to convert into Tl but reverse must be preferred that's why it is more stable than \[T{{l}^{3+}}(E{}^\circ =+1.26).\] In Al,\[A{{l}^{3+}}\]is more stable \[(E{}^\circ =-1.66)\]than \[A{{l}^{+}}(E{}^\circ =+0.55)\]and also from \[T{{l}^{+}}\] due to more negative value of \[E{}^\circ \] Therefore, by comparison it confirms that \[T{{l}^{+}}\]is more stable than \[A{{l}^{+}}.\]
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