NEET Sample Paper NEET Sample Test Paper-92

  • question_answer
    The boiling point of a solution of 0.11 g of a substance in 15 g of ether was found to be \[0.1{}^\circ C\] higher than that of pure ether. The molecular weight of the substance will be \[({{K}_{b}}=2.16\,K\,kg\,mo{{l}^{-1}})\]

    A) \[148\,g\,mo{{l}^{-1}}\]

    B)                    \[158\,g\,mo{{l}^{-1}}\]

    C) \[168\,g\,mo{{l}^{-1}}\]           

    D)        \[178\,g\,mo{{l}^{-1}}\]

    Correct Answer: B

    Solution :

    [b] \[M=\frac{{{K}_{b}}\times w\times 1000}{\Delta {{T}_{b}}\times W}\] \[=\frac{2.16\times 0.11\times 1000}{0.1\times 15}=158.4\]


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