A) unchanged
B) halved
C) doubled
D) quadrupled
Correct Answer: D
Solution :
[d] The fringe width in Young's double slit experiment is \[\beta =\frac{\lambda D}{d}\] where \[\lambda \] is the wavelength of light used. D is the distance between slit and screen, d is the distance between the slit. \[\beta '=\frac{\lambda (2D)}{d/2}=4\frac{\lambda D}{d}=4\beta \]You need to login to perform this action.
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