A) \[1.0\times {{10}^{-12}}\]
B) \[1.0\times {{10}^{-10}}\]
C) \[1.0\times {{10}^{-8}}\]
D) \[1.0\times {{10}^{-16}}\]
Correct Answer: A
Solution :
[a] Solubility of Agt in KI soln.\[=\frac{{{k}_{sp}}\,\,of\,\,AgI}{[{{I}^{-}}]}\] \[=\frac{1.0\times {{10}^{-16}}}{{{10}^{-4}}}=1.0\times {{10}^{-12}}\,mo{{l}^{-1}}\]You need to login to perform this action.
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