A) 34.2 g/lit
B) 17.1 g/lit
C) 18.0 g/lit
D) 36.0 g/lit of glucose
Correct Answer: C
Solution :
[c] For isotonic solutions \[{{\pi }_{1}}={{\pi }_{2}}\]or \[{{c}_{1}}={{c}_{2}};\] \[\frac{34.2}{342}=0.1;\]\[\frac{18.0}{180}=0.1.\] Hence \[18\,\,g{{L}^{-1}}\]glucose is 0.1 M.You need to login to perform this action.
You will be redirected in
3 sec