A) \[\Delta U=-\]W in an adiabatic process
B) \[\Delta U=\]W in an isothermal process
C) \[\Delta U=-\]W in an isothermal process
D) \[\Delta U=\]W in an adiabatic process
Correct Answer: A
Solution :
[a] In adiabatic process Heat change \[\Delta Q=0\] By first law of thermodynamics, \[\Delta Q=\Delta U+W\] \[\Rightarrow \] \[0=\Delta U+W\]\[\Rightarrow \]\[\Delta U=-W\] In isothermal process; Temperature change, \[\Delta T=0\] Change in internal energy, \[\Delta U=n{{C}_{v}}\Delta T=0\] By \[\Delta Q=\Delta U+W\]\[\Rightarrow \]\[\Delta Q=W\]You need to login to perform this action.
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