A) \[0.002\,\,kg\,{{m}^{2}}\]
B) \[0.02\,\,kg\,{{m}^{2}}\]
C) \[2\,\,kg\,{{m}^{2}}\]
D) \[0.2\,\,kg\,{{m}^{2}}\]
Correct Answer: D
Solution :
[d] Moment of inertia of disc about its axis \[=\frac{1}{2}m{{r}^{2}}=\frac{1}{2}\times 0.4\times {{\left( \frac{100}{100} \right)}^{2}}\] \[=\frac{1}{2}\times 0.4=0.2\,kg{{m}^{2}}\]You need to login to perform this action.
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