A) \[\frac{k{{L}^{2}}}{2M}\]
B) \[\sqrt{Mk}\]
C) \[\frac{M{{L}^{2}}}{k}\]
D) zero
Correct Answer: B
Solution :
[b] \[\frac{1}{2}M{{v}^{2}}=\frac{1}{2}k\,\,{{L}^{2}}\] Momentum\[=M\times v=M\times \sqrt{\frac{k}{M}}.L=\sqrt{kM}.L\]You need to login to perform this action.
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