A) \[\frac{I}{{{I}_{{}^\circ }}}=\frac{2}{11}\]
B) \[\frac{I}{{{I}_{{}^\circ }}}=\frac{1}{11}\]
C) \[\frac{I}{{{I}_{{}^\circ }}}=\frac{4}{11}\]
D) \[\frac{I}{{{I}_{{}^\circ }}}=\frac{3}{11}\]
Correct Answer: B
Solution :
[b] \[I'=\frac{{{I}_{0}}\times 2.5}{(25+25)}={{I}_{0}}\times \frac{25}{275}=\frac{1}{11}\times {{I}_{0}}\] \[\Rightarrow \] \[\frac{I'}{{{I}_{0}}}=\frac{1}{11}.\]You need to login to perform this action.
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