A) \[(27/5)\lambda \]
B) \[(5/27)\lambda \]
C) \[(32/27)\lambda \]
D) \[(27/32)\lambda \]
Correct Answer: B
Solution :
[b] For first line of Balmer series \[\frac{1}{\lambda }=R\left( \frac{1}{4}-\frac{1}{9} \right)\]\[\Rightarrow \]\[R=\frac{36}{5\lambda }\] \[\therefore \]Wavelength of the first line, \[{{\lambda }_{L}}\]of the Lyman series is given by \[\frac{1}{{{\lambda }_{L}}}=R\left( 1-\frac{1}{4} \right)=\frac{36}{5\lambda }\times \frac{3}{4}=\frac{27}{5\lambda }\] \[\Rightarrow \]\[{{\lambda }_{L}}=\frac{5\lambda }{27}\]
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