A) 1 : 4
B) 4 : 1
C) 1 : 2
D) 2 : 1
Correct Answer: C
Solution :
[c] \[\frac{{{K}_{1}}}{{{K}_{2}}}=\frac{p_{2}^{1}}{{{m}_{1}}}\times \frac{{{m}_{2}}}{p_{2}^{2}}\]\[[\therefore p=mv\Rightarrow K=\frac{{{p}^{2}}}{2m}]\] Hence,\[\frac{{{p}_{1}}}{{{p}_{2}}}=\sqrt{\frac{{{m}_{1}}}{{{m}_{2}}}}=\sqrt{\frac{1}{4}}=\frac{1}{2}\]You need to login to perform this action.
You will be redirected in
3 sec