A) \[2\,\,{{m}^{-1}}\]
B) \[0.5\,{{m}^{-1}}\]
C) \[6\,{{m}^{-1}}\]
D) \[3\,{{m}^{-1}}\]
Correct Answer: A
Solution :
[a] On comparing the given equation to \[\overrightarrow{E}={{a}_{0}}\hat{i}\cos (\omega t-kz)\] \[\omega =6\times {{10}^{8}},\] \[k=\frac{2\pi }{r}=\frac{\omega }{c}\] \[k=\frac{\omega }{c}=\frac{6\times {{10}^{8}}}{3\times {{10}^{8}}}=2\,{{m}^{-1}}\]
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