A) 15 cm above the target
B) 10 cm above the target
C) 2.2 cm above the target
D) directly towards the target
Correct Answer: C
Solution :
[c] The bullet performs a horizontal journey of 100 cm with constant velocity of 1500 m/s. The bullet also performs a vertical journey of h with zero initial velocity and downward acceleration g. \[\therefore \] For horizontal journey, time (t) \[\text{=}\frac{\text{Distance}}{\text{Velocity}}\] \[\therefore \] \[t=\frac{100}{1500}=\frac{1}{15}\sec \] ?(1) The bullet performs vertical journey for this time. For vertical journey, \[h=ut+\frac{1}{2}g{{t}^{2}}\] \[h=0+\frac{1}{2}\times 10\times {{\left( \frac{1}{15} \right)}^{2}}\] or, \[h=\frac{20}{9}cm=2.2cm\]
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