A) \[-\frac{3E}{2}\]
B) \[-E\]
C) \[-\frac{E}{2}\]
D) \[-2E\]
Correct Answer: C
Solution :
[c] Field at Q is E. So, force on \[Q=QE\] This force will be applied on \[-2Q.\] Also according to Coulomb's law. So, field at \[-2Q\] is \[\frac{QE}{-2Q}=-\frac{E}{2}.\]You need to login to perform this action.
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