A) \[R=r\]
B) \[R<r\]
C) \[R>r\]
D) \[R={r}/{2}\;\]
Correct Answer: A
Solution :
[a] \[I=\frac{E}{R+r}\] \[=\frac{E}{[{{(\sqrt{R})}^{2}}+{{(\sqrt{r})}^{2}}-2\sqrt{2r}]+2\sqrt{Rr}}\] \[=\frac{E}{{{(\sqrt{R}-\sqrt{r})}^{2}}+2\sqrt{Rr}}\] I will be maximum if \[(\sqrt{R}-\sqrt{r})=0\] or \[R=r\]
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