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NEET Sample Paper NEET Sample Test Paper-93

  • question_answer
    In A.C. circuit in which inductance and capacitance are joined in series, current is found to be maximum when the value of inductance is 0.5 H and the value of capacitance is \[8\mu F.\] The angular frequency of applied alternating voltage will be

    A) \[400\,Hz\]        

    B)        \[5000\,Hz\]

    C) \[2\times {{10}^{5}}\,Hz\]       

    D)        \[500\,Hz\]

    Correct Answer: D

    Solution :

    [d] Current is max at resonance condition So, \[\omega =\frac{1}{\sqrt{LC}}=\frac{1}{\sqrt{0.5\times 8\times {{10}^{-6}}}}\] \[\omega =\frac{1}{\sqrt{4\times {{10}^{-6}}}}\] \[\omega =\frac{1\times 1000}{2}\] \[\omega =500\,Hz\]


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