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NEET Sample Paper NEET Sample Test Paper-93

  • question_answer
    10 gm of ice cubes at \[0{}^\circ C\] are released in a tumbler (water equivalent 55 g) at \[40{}^\circ C.\] Assuming that negligible heat is taken from the surroundings, the temperature of water in the tumbler becomes nearly \[(L=80{cal}/{g}\;)\]

    A) \[31{}^\circ C\]

    B)        \[22{}^\circ C\]

    C) \[19{}^\circ C\]

    D)        \[15{}^\circ C\]

    Correct Answer: B

    Solution :

    [b] Let the final temperature be T Heat gained by ice \[=mL+m\times s\times (T-0)\] \[=10\times 80+10\times 1\times T\] Heat lost by water \[=55\times 1\times (40-T)\] By using law of calorimetery, \[800+10\,T=55\times (40-T)\] \[\Rightarrow \]\[T=21.54{}^\circ C=22{}^\circ C\]


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