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NEET Sample Paper NEET Sample Test Paper-93

  • question_answer
    In Young's double-slit experiment, the separation between the slits is halved and the distance between the slits and the screen is doubled. The fringe width is

    A) unchanged        

    B)        halved

    C) doubled

    D)        quadrupled

    Correct Answer: D

    Solution :

    [d] The fringe width in Young's double slit experiment is \[\beta =\frac{\lambda D}{d}\] where \[\lambda \] is the wavelength of light used. D is the distance between slit and screen, d is the distance between the slit. \[\beta '=\frac{\lambda (2D)}{d/2}=4\frac{\lambda D}{d}=4\beta \]


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