| \[4N{{H}_{3}}(g)+5{{O}_{2}}(g)\xrightarrow{Pt(s)}4NO(g)+6{{H}_{2}}O(g)\] |
| (i) Rate of reaction with respect to \[N{{H}_{3}}\]will be \[-\frac{1}{4}\frac{\Delta [N{{H}_{3}}]}{\Delta t}\] |
| (ii) For the given reaction \[-\frac{1}{5}\frac{\Delta [{{O}_{2}}]}{\Delta t}=\frac{-1}{6}\frac{\Delta [{{H}_{2}}O]}{\Delta t}\] |
| (iii) For the given reaction \[-\frac{1}{4}\frac{\Delta [N{{H}_{3}}]}{\Delta t}=\frac{1}{4}\frac{\Delta [NO]}{\Delta t}\] |
| (iv) For the given reaction, Rate\[=-\frac{1}{4}\frac{\Delta [N{{H}_{3}}]}{\Delta t}=-\frac{1}{5}\frac{\Delta [{{O}_{2}}]}{\Delta t}\] \[=\frac{4\Delta [NO]}{\Delta t}=\frac{6\Delta [{{H}_{2}}O]}{\Delta t}\] |
| Which of the following are the correct statements. |
A) (i) and (iv)
B) (i) and (iii)
C) (ii) and (iv)
D) All are correct
Correct Answer: B
Solution :
[b] For the given reaction \[4N{{H}_{3}}(g)+5{{O}_{2}}(g)\xrightarrow{pt(s)}4NO(g)+6{{H}_{2}}O(g)\] Rate\[=\frac{-1}{4}\frac{\Delta [N{{H}_{3}}]}{\Delta t}=\frac{-1}{5}\frac{\Delta [{{O}_{2}}]}{\Delta t}=\frac{1}{4}\frac{\Delta [NO]}{\Delta t}\] \[=\frac{1}{6}\frac{\Delta [{{H}_{2}}O]}{\Delta t}\]
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