A) \[32\pi {{R}^{2}}T\]
B) \[24\pi {{R}^{2}}T\]
C) \[8\pi {{R}^{2}}T\]
D) \[4\pi {{R}^{2}}T\]
Correct Answer: B
Solution :
[b] When radius is doubled, increase in surface area \[=2\times 4\pi (4{{R}^{2}}-{{R}^{2}})\] \[=2\times 4\pi \times 3{{R}^{2}}=24\pi {{R}^{2}}\] Work done = Increase in area \[\times \] T \[=24\pi {{R}^{2}}T.\]
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