2. Sample Papers
  3. NEET

NEET Sample Paper NEET Sample Test Paper-93

  • question_answer
    The solubility product of AgI at \[25{}^\circ C\] is \[1.0\times {{10}^{-16}}mo{{l}^{2}}{{L}^{-2}}.\] The solubility of AgI in\[{{10}^{-4}}N\] solution of KI at \[25{}^\circ C\] is approximately (in \[mol\,{{L}^{-1}}\])

    A) \[1.0\times {{10}^{-12}}\]        

    B)        \[1.0\times {{10}^{-10}}\]

    C) \[1.0\times {{10}^{-8}}\]         

    D)        \[1.0\times {{10}^{-16}}\]

    Correct Answer: A

    Solution :

    [a] Solubility of Agt in KI soln.\[=\frac{{{k}_{sp}}\,\,of\,\,AgI}{[{{I}^{-}}]}\] \[=\frac{1.0\times {{10}^{-16}}}{{{10}^{-4}}}=1.0\times {{10}^{-12}}\,mo{{l}^{-1}}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner