NEET Sample Paper NEET Sample Test Paper-93

  • question_answer
    A particle of mass m is fixed to one end of a light spring of force constant k and unstretched length \[\ell \] The system is rotated about the other end of the spring with an angular velocity \[\omega ,\] in gravity free space. The increase in length of the spring will be

    A) \[\frac{m{{\omega }^{2}}\ell }{k}\]      

    B)        \[\frac{m{{\omega }^{2}}\ell }{k-m{{\omega }^{2}}}\]

    C) \[\frac{m{{\omega }^{2}}\ell }{k+m{{\omega }^{2}}}\]          

    D)        None of these

    Correct Answer: B

    Solution :

    [b] Let x = the increase in the length of spring. Then the particle moves along a circular path of radius \[(\ell +x),\] and the spring force = kx = centripetal force \[\therefore \]\[m{{\omega }^{2}}(\ell +x)=kx\] or \[x=\frac{m{{\omega }^{2}}\ell }{k-m{{\omega }^{2}}}\]


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