A) \[{{10}^{-33}}\text{metres}\]
B) \[{{10}^{-31}}\text{metres}\]
C) \[{{10}^{-16}}\text{metres}\]
D) \[-N{{H}_{2}}\] Planck's constant, \[h=6.63\times {{10}^{-34}}Js\]
Correct Answer: A
Solution :
[a] \[\lambda =\frac{h}{mv}=\frac{6.63\times {{10}^{-34}}}{0.060\times 10}=1.1\times {{10}^{-33}}m\]
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