A) \[=\left( \frac{M}{m}-1 \right)g\]
B) \[>\left( \frac{M}{m}-1 \right)g\]
C) \[\frac{M}{m}g\]
D) \[>\frac{M}{m}g\]
Correct Answer: B
Solution :
Equation of motion for M, Since M is stationary \[T-Mg=0\] \[T=Mg\] ?.(i) Since, the monkey moves up with an acceleration a \[T-mg=ma\] \[T-m(g+a)\] ?..(ii) Equating equations (i) and (ii), we obtain \[Mg=m(g+a)\] \[a=\left( \frac{M}{m}-1 \right)g\] That means, if \[a>\left( \frac{M}{m}-1 \right)g,\] the block M can be lifted from the floor.You need to login to perform this action.
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