A) \[6m{{s}^{-2}}\]
B) \[8m{{s}^{-2}}\]
C) \[10m{{s}^{-2}}\]
D) \[14m{{s}^{-2}}\]
Correct Answer: C
Solution :
Given that, \[X={{t}^{3}},\,Y=4{{t}^{2}},Vx=3{{t}^{2}}\] and \[{{a}_{x}}=6t\] (at \[t=1s\]) \[=6m/{{s}^{2}}\] \[{{V}_{Y}}=8t,{{a}_{Y}}=8m/{{s}^{2}}\] (at \[t=15\]) \[a=\sqrt{a_{X}^{2}+a_{Y}^{2}}\] \[a=\sqrt{{{(6)}^{2}}+{{(8)}^{2}}}=10m/{{s}^{2}}\]You need to login to perform this action.
You will be redirected in
3 sec