A) \[2.5\,V\]
B) \[5.9\,V\]
C) \[5\,V\]
D) \[1.1\,V\]
Correct Answer: B
Solution :
As energy associated with the photon is given by: \[\frac{hc}{\lambda }=h\upsilon \] \[=2.5+1.7=4.2eV\] and \[\upsilon \lambda =c\] Now, \[V'\frac{\lambda }{2}=c\] \[\Rightarrow \] \[V'=2V\] \[\Rightarrow \] \[e{{V}_{0}}=h\,(2V)-\phi \] \[=2\times 4.2-2.5\] \[{{V}_{0}}=5.9V\]You need to login to perform this action.
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