A) zero
B) \[\frac{pq}{4\pi {{\varepsilon }_{0}}{{R}^{3}}}\]
C) \[\frac{pq}{2\pi {{\varepsilon }_{0}}{{R}^{3}}}\]
D) \[\frac{pq}{4\pi {{\varepsilon }_{0}}{{R}^{3}}},\] only if the charge uniformly distributed on the ring.
Correct Answer: B
Solution :
The electric field due to the dipole on the circumference of the ring, \[E=\frac{P}{4\pi {{\varepsilon }_{0}}{{R}^{3}}}\] and it is directed normal to the plane charged ring. Hence, force on the charged ring \[F=qE=\frac{Pq}{4\pi {{\varepsilon }_{0}}{{R}^{3}}}\]You need to login to perform this action.
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