A) \[4/3\]
B) \[1/2\]
C) \[1/3\]
D) \[3/2\]
Correct Answer: D
Solution :
Suppose electric field in dielectric are \[{{E}_{1}}\] and \[{{E}_{2}}\] \[\Rightarrow \] \[\frac{\Delta {{V}_{1}}}{\Delta {{V}_{2}}}=\frac{{{E}_{1}}d}{{{E}_{2}}2d}=\frac{3}{2}\] \[\left( \because \,\,\frac{{{E}_{1}}}{{{\varepsilon }_{1}}}=\frac{{{K}_{2}}}{{{K}_{1}}}=3 \right)\]You need to login to perform this action.
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