A) 3 km
B) 4 km
C) 5 km
D) 7 km
Correct Answer: C
Solution :
The movements of a man are as shown \[EF=\left( DE-DF \right)=\left( 9-5 \right)km=4\text{ }km~~\] BF = CD = 2 km and AF =AB + BF = 3 km \[\therefore \,\,\,~A{{E}^{2}}=\text{ }A{{F}^{2}}+\text{ }E{{F}^{2}}={{3}^{2}}+\text{ }{{4}^{2}}=25~\]\[\Rightarrow ~~\]ZE = 5 kmYou need to login to perform this action.
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