A) 12m
B) 20m
C) 28m
D) 48m
Correct Answer: B
Solution :
[b] Displacement along x-axis \[=4\times 3=12\]m Displacement along y-axis \[=\frac{1}{2}a{{t}^{2}}\] \[=\frac{1}{2}\left( \frac{4}{2} \right){{(4)}^{2}}\] =16m Resultant displacement \[=\sqrt{{{(12)}^{2}}+{{(16)}^{2}}}\] \[=\sqrt{144+256}\] =20mYou need to login to perform this action.
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