A) Only 1 value
B) 2 values
C) 3 values
D) No value
Correct Answer: B
Solution :
[b] \[{{x}^{1/3}}=y\] \[\therefore \text{ }{{y}^{2}}+y-2=0\] \[\left( y+2 \right)\left( y-1 \right)=0,\]which gives \[y=1,-2\] or x = 1 or \[x\text{ }=-\text{ }8\]are the solutions, hence 2 valuesYou need to login to perform this action.
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