NTSE Sample Paper NTSE SAT Practice Test-11

  • question_answer
    The focal length of a lens whose power is -1.5 D is

    A) -66.6cm     

    B)        +1.5m

    C) +66.6 cm         

    D)        -1.5m

    Correct Answer: A

    Solution :

    [a] Power = \[\frac{1}{Focal\text{ }length\text{ }\left( in\text{ }metre \right)}\] \[-1.5=\frac{1}{f}\] or  \[f=-\left( \frac{1\times 100}{1.5} \right)\,\,cm\] \[=\text{ }-\text{ }66.6\text{ }cm\]         


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