A) 1
B) 2
C) 3
D) 4
Correct Answer: A
Solution :
[a] \[\frac{1}{x}=\frac{a+b}{a-b}\] Or \[\frac{1+x}{1-x}=\frac{a}{b}\] Also, \[\frac{1+y}{1-y}=\frac{b}{c}\]and \[\frac{1+z}{1-z}=\frac{c}{a}\] \[\therefore \,\,\,\left( \frac{1+x}{1-x} \right)\times \left( \frac{1+y}{1-y} \right)\times \left( \frac{1+z}{1-z} \right)\] \[=\frac{a}{b}\times \frac{b}{c}\times \frac{c}{a}=1\]You need to login to perform this action.
You will be redirected in
3 sec