NTSE Sample Paper NTSE SAT Practice Test-12

  • question_answer
    Two charges are placed a certain distance apart in air. If a glass slab is introduced between them, the force between them will

    A) Increase            

    B)        Decrease

    C) Remain the same           

    D) Be zero

    Correct Answer: B

    Solution :

    [b] \[{{F}_{g}}=\frac{1}{4\pi \varepsilon ,,}\left( \frac{{{q}_{1}}{{q}_{2}}}{{{r}_{2}}} \right)=\frac{{{F}_{a}}}{k}\] As k (for glass) > 1, we have \[{{F}_{g}}<{{F}_{a}}\]


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