A) 7 : 6
B) 7 : 12
C) 11 : 10
D) 10: 11
Correct Answer: A
Solution :
[a] \[{{y}^{3}}=4x\times 2x\times x=8{{x}^{3}}\] or \[y=2x\] \[\frac{Surface\text{ }area\text{ }of\text{ }cuboid}{Surface\text{ }area\text{ }of\text{ }cube}\]\[=\frac{2(2{{x}^{2}}+4{{x}^{2}}+8{{x}^{2}})}{6{{y}^{2}}}\] \[=\frac{28{{x}^{2}}}{24{{x}^{2}}}\] \[=\frac{7}{6}\]You need to login to perform this action.
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